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How do I compute the +4 charge state m/z for a peptide of 4731.3 Da?

Asked 6 Jul 2025Modified 11 months agoViewed 19k times
25

For reference: +4 · 4731.3 Da.

I would rather understand the derivation than memorise the outcome.

Two people I asked gave two answers that differ by a factor of ten, which is suggestive.

Can someone walk through the arithmetic step by step?

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GS
askedgradient_slope41k386 Jul 2025
2Do you have a reference for the last claim? Not disputing it, just want to read it. – j_wierzbicki 9 months ago
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1 Answer

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The underlying point is that a mass shift of exactly zero with a shifted retention time points to an isomer — a scrambled disulfide or a racemised residue — which mass spectrometry alone cannot identify.

Deconvolution of a mass spectrum with multiple charge states produces a reconstructed neutral mass, and errors in the deconvolution produce errors in the inferred mass.

What each test answers

TestAnswersDoes NOT answer
RP-HPLC, area %What fraction of detected material is the targetHow much target is present
Quantified contentMilligrams of peptide per vialWhat the impurities are
ESI-MS identityWhether the molecular weight matchesPurity, or isomeric substitution
Peptide mappingSequence, localised to a fragmentQuantity
Karl FischerWater content of the solidSolvent content
LAL endotoxinPyrogen load in EU/mgSterility
Sterility testGrowth in defined media over 14 daysEndotoxin, or bioburden count

A mass shift of minus eighteen usually means dehydration or a succinimide intermediate, which is pH-dependent and can be reversible.

Electrospray ionisation soft-ionisation behaviour is well-characterised and standards exist for m/z calibration and mass accuracy assessment.

Always run a blank between samples and check for carry-over.

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TG
answeredtandem_gradient85k24822 Aug 2025
2Do you have a reference for the last claim? Not disputing it, just want to read it. – triple_agonist_q 5 months ago
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