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Why does oxidation accelerate at minus 80 °C rather than proceeding linearly?

Asked 17 Feb 2025Modified 13 months agoViewed 32k times
19

The case in front of me: oxidation · minus 80 °C.

This is one of those things that everyone repeats and nobody derives.

This matters practically, not just academically, because it changes what I would do next.

Why does this happen, and what would falsify the usual explanation?

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RP
askedrhian_prydderch23k2717 Feb 2025

5 Answers

Accepted answer first, then by votes
18

Accepted answer

Because temperature enters the rate constant through an exponential, so equal steps in temperature multiply the rate instead of adding to it. Arrhenius puts the rate proportional to exp(−Ea/RT); the working approximation is a doubling per 10 K, which takes 5, 15, 25 and 35 °C to multipliers of 1, 2, 4 and 8. The steps in temperature are equal and the steps in rate are not, and that is the whole of the observation. At minus 80 °C the same rule gives no useful multiplier at all, because below freezing the reaction is no longer happening in bulk solution. Met and Trp take up oxygen sixteen daltons at a time, and the oxidised species is more polar, so on a reversed-phase column it elutes ahead of the parent rather than behind it. Ea differs by route, so the ranking of routes changes with temperature too — which is why accelerated data extrapolates badly and why nobody should read a 40 °C study as a fast version of a 5 °C one.

The relevant point is that a mass shift of plus one dalton is deamidation and plus sixteen is oxidation, so degradation is often visible in a mass spectrum if anyone looks.

Adsorption onto glass and plastic is significant at low concentrations — micrograms per millilitre — and negligible at milligrams per millilitre. It is the usual explanation for an apparent loss in a dilute preparation.

Reported and extrapolated stability by condition

StateConditionUsable windowBasis
Lyophilised solid−20 °C, sealed, dry24–36 monthsSupplier guidance
Lyophilised solid2–8 °C, sealed12–24 monthsSupplier guidance
Lyophilised solid25 °C, sealed4–8 weeksExtrapolated (Arrhenius)
Lyophilised solid40 °C, sealed1–2 weeksExtrapolated
Solution, preserved2–8 °C28 daysUSP microbiological convention
Solution, preserved25 °C3–7 daysExtrapolated
Solution, unpreserved2–8 °C24 hoursUSP microbiological convention

Windows for the solid state are chemical; windows for solution are microbiological and usually shorter than the chemical limit.

It helps to be literal here: light exposure matters for tryptophan-containing sequences and for anything with a chromophore. Amber vials and a closed box are free mitigations.

Metal-catalysed oxidation of methionine is documented across peptide and protein formulations and is why chelators appear in some formulations.

Nothing here is medical advice, and research-use compounds are not approved for human use.

Swirl, never shake. Aggregation is a handling problem more than a time problem.

edited 12 Mar 2025 by haze_check — corrected a unit error in the worked example

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HC
answered · acceptedhaze_check9.3k169 Mar 2025
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16

Answering this needs the physical state, since a dry powder is protected from most of these and a solution is protected from none.

Freeze-thaw cycling drives aggregation through concentration at the ice interface and pH shifts as buffer components crystallise out at different rates. Each cycle costs something.

A mass spectrum resolves most of this: minus eighteen is dehydration or succinimide, plus one is deamidation, plus sixteen is oxidation, and an unchanged mass with a shifted retention time is an isomer.

Deamidation via the succinimide intermediate is well characterised, with sequence-dependent rates highest for asparagine-glycine motifs.

Sequence decides which pathways are even available. Check the residues.

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BU
answeredbufferline4230k13826 Feb 2025
8

Asparagine and glutamine are the deamidation risk, and methionine is the oxidation risk.

Oxidation targets methionine, cysteine and tryptophan, adding sixteen daltons per oxygen. It is catalysed by trace metals and promoted by dissolved oxygen and by light.

Specifically, hydrolysis cleaves the backbone, most readily at aspartate-proline and aspartate-glycine sequences, and is acid-catalysed. In a dry solid it barely proceeds at all.

Adsorption losses at low concentrations are quantified in formulation studies and are the reason carrier proteins are used in dilute preparations.

Sequence determines which pathways apply, so general statements are general.

Cold, dry, dark, still. Those four words cover most of the mitigation.

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ND
answerednynke_dekker9.4k1712 May 2025
6

Put another way, this is answerable from the chemistry rather than from anecdote, which is unusual and welcome.

Aggregation is physical: peptides unfold at air-liquid interfaces and associate. Shaking maximises that interface, which is why swirling and shaking produce visibly different outcomes on the same vial.

Aggregation at air-liquid interfaces is established from surface-tension and particle-count studies and is the basis for anti-agitation handling guidance.

Apparent loss in a dilute preparation is usually adsorption rather than degradation and is worth ruling out first.

At dilute concentrations, suspect adsorption before you suspect chemistry.

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MO
answeredmarta_okonkwo190k2583 Jun 2025
4Is there a reason to prefer minus eighty here, or is minus twenty genuinely enough? – Dr_Priya_Raghunathan 5 months ago
5This should be linked from the help pages. – mass_shift_18 7 months ago
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4

The honest answer is that most reported "degradation" is adsorption and dilution error rather than chemistry.

Deamidation converts asparagine or glutamine to the corresponding acid via a succinimide intermediate, adding one dalton. It is base-catalysed, accelerates above neutral pH and is the dominant aqueous pathway for many peptides.

Deamidation kinetics for asparagine in peptides are well characterised and strongly sequence-dependent: the residue following the asparagine dominates the rate, with glycine and serine at the n+1 position accelerating it by an order of magnitude relative to bulkier residues. That is why two peptides in the same buffer at the same temperature can have quite different shelf lives.

The caveat is that none of these pathways can be seen by looking at a vial, and a clear solution can be substantially degraded.

A mass spectrum names the pathway. Plus one, plus sixteen, minus eighteen.

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JW
answeredj_wierzbicki69k14815 Jun 2025
5Adding a vote because this deserves more of them. – fib4_reader 4 months ago
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Your answer

Ask PeptideStack is a static archive. Posting is closed, but the norms are worth stating: answer the question that was asked, show your working, cite the trial or the certificate, and say plainly where the evidence runs out.

Not medical advice. Research-use-only compounds are not approved for human use.