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Is an MKM order from Shanghai likely to hold cold chain to Sweden?

Asked 6 Dec 2024Modified 17 months agoViewed 13k times
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For reference: MKM · Shanghai · Sweden.

I am at the decision point and I would rather think it through than improvise.

I would rather spend money on measurement than on redundancy.

What is the minimum version of this that is still defensible?

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askedcoldbox913k286 Dec 2024

2 Answers

Accepted answer first, then by votes
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Accepted answer

Freeze-thaw damage happens at the moving ice front, not at the storage temperature. Once the sample is frozen solid and cold, very little is happening. The damage is done during freezing and thawing, which is why the number of cycles matters and the duration of the hold mostly does not.

Adsorption to the container is a real loss at low concentration. For a peptide at 0.1 mg/mL in an untreated glass vial, single-digit percentage losses to the wall are plausible; at 5 mg/mL it is negligible. This is one of several reasons not to reconstitute to a very dilute working solution and store it.

Degradation pathway by condition

PathwayDominant whenDetected by
DeamidationSolution, neutral to alkaline pHRP-HPLC, +1 Da on MS
OxidationLight, trace metals, peroxidesRP-HPLC, +16 Da on MS
HydrolysisSolution, extremes of pHRP-HPLC, fragment masses
AggregationAgitation, interfaces, high concentrationSEC, visual haze; often invisible on RP-HPLC
Freeze-concentration damageFreeze-thaw of buffered solutionSEC, loss of recovered content

More usefully, aggregation is the failure mode that reverse-phase HPLC is worst at detecting, because a large soluble aggregate may not elute at all and an insoluble one is filtered out during sample preparation. If your purity result comes back normal but the vial looks hazy, believe the vial. Size-exclusion chromatography is the method that sees this.

Deamidation kinetics for asparagine in peptides are well characterised and strongly sequence-dependent: the residue following the asparagine dominates the rate, with glycine and serine at the n+1 position accelerating it by an order of magnitude relative to bulkier residues. That is why two peptides in the same buffer at the same temperature can have quite different shelf lives.

The practical rule is that time and temperature multiply, so shorten whichever one you control.

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answered · acceptedorla_ferriter47k3810 Jan 2025
8Thank you — the worked example is what makes this usable. – tabular_nums 7 months ago
Related: the same reasoning applies to the counter-ion question. – vialroom 8 months ago
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54

More usefully, a warm arrival is a reason to test, not automatically a reason to discard. Peptide degradation is kinetic — rate multiplied by time — and a few days at thirty degrees in the solid state is a small integral compared to weeks in solution.

Light matters for specific residues rather than in general. Tryptophan and to a lesser extent tyrosine and methionine are photo-labile; a sequence without them is largely indifferent to ambient light over the timescales in question. Amber glass is cheap insurance rather than a requirement.

Concretely, on re-freezing something that thawed in transit: if it arrived as a lyophilised solid that warmed but never got wet, re-freezing costs you nothing except the thermal cycle. If it arrived as a solution that thawed, re-freezing adds a second transition and therefore a second dose of ice-front shear. The asymmetry is worth internalising.

Minimise transitions rather than minimising temperature. One freeze and one thaw is fine; five is a different question.

edited 20 Feb 2025 by imani_dube — reworded for clarity after a comment

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answeredimani_dube19k2821 Jan 2025
4Worth flagging that this changed in 2025, so older answers on the site are out of date. – cap_the_luer 10 months ago
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