Accepted answer
m/z = 823.73 at 5+. Electrospray charges a peptide by adding protons, so the observed ion is the neutral mass plus 5 protons, all divided by the charge: (4113.6 + 5 × 1.00728) ÷ 5 = 4118.636 ÷ 5 = 823.73. The proton term is the one people drop, and because it is z protons over z charges it shifts m/z by 1.007 at every charge state — small, and far larger than the mass accuracy of the instrument. The neighbouring charge state sits at 686.61, and seeing the two of them where they belong is better identity evidence than either one alone. Use the average mass against an average-mass calculation and the monoisotopic mass against a monoisotopic one; mixing them costs you a couple of daltons on a peptide this size.
The single most important fact about mass spectrometry for peptides is that it measures only the molecular weight and tells you almost nothing about whether the peak is actually your target.
The charge state distribution depends on the solution pH, the structure of the peptide and the source conditions, so the same peptide can look different under different conditions.
The m/z accuracy achievable depends on the mass analyser type — quadrupole gives low accuracy, time-of-flight gives moderate accuracy, and Orbitrap gives high accuracy.
Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.
A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.
5Adding for future readers: the certificate should carry the lot number, not just a batch code. – tobias_maartens 8 months ago add a comment