Accepted answer
97.1 per cent is a statement about area, and the other 2.9 per cent is everything the detector saw and did not assign to your peak. Read it as 97.1 of every 100 units of peak area at whatever wavelength was used, not as 97.1 per cent of the mass in the vial. With the chromatogram attached you can at least see how the figure was produced, which is the difference between a measurement and a claim. What it still does not tell you is content: how many milligrams are actually there.
Purity is a method-dependent figure, and that is not a limitation of the measurement, it is a property of what the measurement actually answers.
Detection wavelength matters because 214 nm sees the peptide backbone while 280 nm sees only aromatic side chains — so truncation impurities lacking a tryptophan are invisible at 280 nm.
Reconciling gross mass to label claim
| Component | Typical share | Counted in purity? | Counted in content? |
|---|
| Target peptide | 88–94 % | Yes, as main peak | Yes |
| Related impurities | 1–3 % | Yes, as other peaks | No |
| Counter-ion (TFA or acetate) | 2–8 % | No | No |
| Residual water | 2–6 % | No | No |
| Bulking agent, if present | 0–40 % | No | No |
In practice, temperature affects the dynamics of molecular conformation, and if a peptide has proline residues that interconvert on the chromatographic timescale, the peak will split or shoulder at low temperature and collapse at high temperature.
Inter-laboratory studies on identical peptide material routinely find half-a-per-cent to a full-per-cent spreads in reported purity on the same sample.
If you are ranking vendors, specify a method and have all samples tested at the same place.
6Confirming from the other direction: I ignored the method section once and paid for it. – w_okoye 9 months ago 7Does this hold for a longer chain length, where the deletion sequences accumulate? – lyoph_cake 17 days ago add a comment