Accepted answer
m/z = 1052.81 at 4+. Electrospray charges a peptide by adding protons, so the observed ion is the neutral mass plus 4 protons, all divided by the charge: (4207.2 + 4 × 1.00728) ÷ 4 = 4211.229 ÷ 4 = 1052.81. The proton term is the one people drop, and because it is z protons over z charges it shifts m/z by 1.007 at every charge state — small, and far larger than the mass accuracy of the instrument. The neighbouring charge state sits at 842.45, and seeing the two of them where they belong is better identity evidence than either one alone. Use the average mass against an average-mass calculation and the monoisotopic mass against a monoisotopic one; mixing them costs you a couple of daltons on a peptide this size.
Mass spectrometry is an identity technique, not a purity technique, and conflating the two is a common source of false confidence.
The m/z accuracy achievable depends on the mass analyser type — quadrupole gives low accuracy, time-of-flight gives moderate accuracy, and Orbitrap gives high accuracy.
Reconciling gross mass to label claim
| Component | Typical share | Counted in purity? | Counted in content? |
|---|
| Target peptide | 88–94 % | Yes, as main peak | Yes |
| Related impurities | 1–3 % | Yes, as other peaks | No |
| Counter-ion (TFA or acetate) | 2–8 % | No | No |
| Residual water | 2–6 % | No | No |
| Bulking agent, if present | 0–40 % | No | No |
For a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.
False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.
The caveat is that a correct mass does not mean the peak is correct — isomers and co-eluting species can have the same m/z.
The practical summary: use mass spectrometry for identity, not for purity.