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How do I compute the +5 charge state m/z for a peptide of 4813.5 Da?

Asked 4 Oct 2024Modified 19 months agoViewed 51k times
27

The case in front of me: +5 · 4813.5 Da.

I want the working, not the result — I need to be able to redo it with different numbers.

I care about the precision as well as the value — I want to know how many figures are real.

How many significant figures are actually justified here?

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LF
askedleah_ferrers15k274 Oct 2024

5 Answers

Accepted answer first, then by votes
89

Accepted answer

More usefully, the single most important fact about mass spectrometry for peptides is that it measures only the molecular weight and tells you almost nothing about whether the peak is actually your target.

The baseline noise on a mass spectrum sets the limit of detection, and a weak signal close to the noise is not reliable evidence for the presence of a species.

What each test answers

TestAnswersDoes NOT answer
RP-HPLC, area %What fraction of detected material is the targetHow much target is present
Quantified contentMilligrams of peptide per vialWhat the impurities are
ESI-MS identityWhether the molecular weight matchesPurity, or isomeric substitution
Peptide mappingSequence, localised to a fragmentQuantity
Karl FischerWater content of the solidSolvent content
LAL endotoxinPyrogen load in EU/mgSterility
Sterility testGrowth in defined media over 14 daysEndotoxin, or bioburden count

Mechanically, deconvolution of a mass spectrum with multiple charge states produces a reconstructed neutral mass, and errors in the deconvolution produce errors in the inferred mass.

Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.

One qualification: high-resolution mass spectrometry gives high mass accuracy but low speed, and the reverse is true for low-resolution instruments.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

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FR
answered · acceptedfib4_reader35k3825 Nov 2024
5For what it is worth, my own result was within half a per cent of this. – Dr_Priya_Raghunathan 2 months ago
6Any reason this would differ for a longer peptide? – thermal_mass 4 months ago
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34

Two ions with the same nominal mass but different molecular formulae have different exact masses, and only high-resolution mass spectrometry can distinguish them.

A monoisotopic mass includes only the lightest isotope of each element, while the average mass weights by natural isotope abundance, and small peptides use monoisotopic mass.

Stated carefully, for a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.

Electrospray ionisation soft-ionisation behaviour is well-characterised and standards exist for m/z calibration and mass accuracy assessment.

Worth noting that source contamination is common and silent, so a result that looks too good to be true often is.

The practical summary: use mass spectrometry for identity, not for purity.

edited 30 Dec 2024 by RP_C18 — added the placebo-arm figures

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RC
answeredRP_C1885k1587 Dec 2024
25

A mass shift of exactly zero with a shifted retention time points to an isomer — a scrambled disulfide or a racemised residue — which mass spectrometry alone cannot identify.

High-resolution mass spectrometry can distinguish a Lys-containing peptide from an Arg-containing peptide of similar mass because of the isotope difference.

A mass shift of minus eighteen usually means dehydration or a succinimide intermediate, which is pH-dependent and can be reversible.

The limitation is that mass spectrometry tells you the mass and almost nothing else, so it needs to be paired with chromatography or other identity information.

Always run a blank between samples and check for carry-over.

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AL
answereda_lindgren46k1383 Nov 2024
4I have seen exactly this failure mode twice and both times it was the diluent. – Dr_Ravi_Selvarajah 7 months ago
5The distinction between purity and content cannot be repeated often enough here. – h_pergande 8 months ago
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20

The underlying point is that tandem mass spectrometry fragments the ions and measures the fragment masses, which provides sequence information and is the best tool for confirming identity.

A mass shift of plus one usually means deamidation at asparagine or glutamine, which creates a secondary amine instead of an amide and changes the mass by exactly one.

False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

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LW
answeredlinnea_wahlberg14k1812 Oct 2024
19

Stated carefully, identity confirmation from mass spectrometry means matching the observed m/z to the calculated m/z for your peptide at its known charge states.

Electrospray ionisation creates multiple charge states of the same peptide — a 4 kDa peptide might appear at +2, +3 and +4 — and all of them must be accounted for in the spectrum.

The practical summary: use mass spectrometry for identity, not for purity.

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DR
answeredDr_Priya_Raghunathan94k24815 Nov 2024
2Adding for future readers: the certificate should carry the lot number, not just a batch code. – retest_please 3 months ago
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