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How do I compute the +3 charge state m/z for a peptide of 4207.2 Da?

Asked 25 Jan 2026Modified 4 months agoViewed 2.9k times
5

Setup, so nobody has to ask: +3 · 4207.2 Da.

The units are where I keep going wrong, so please be explicit about them.

I have sanity-checked the order of magnitude and it seems right, which is not the same as being right.

Where is my error, and what is the correct working?

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askedpierce_count15k2825 Jan 2026

3 Answers

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13

On the detail: a mass shift of exactly zero with a shifted retention time points to an isomer — a scrambled disulfide or a racemised residue — which mass spectrometry alone cannot identify.

For a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.

Reconciling gross mass to label claim

ComponentTypical shareCounted in purity?Counted in content?
Target peptide88–94 %Yes, as main peakYes
Related impurities1–3 %Yes, as other peaksNo
Counter-ion (TFA or acetate)2–8 %NoNo
Residual water2–6 %NoNo
Bulking agent, if present0–40 %NoNo

It helps to be literal here: a monoisotopic mass includes only the lightest isotope of each element, while the average mass weights by natural isotope abundance, and small peptides use monoisotopic mass.

I would not trust a mass result without a good baseline and a blank injection check.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

edited 20 Mar 2026 by plate_count_9k — updated for the 2026 guidance change

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answeredplate_count_9k95k15812 Mar 2026
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8

Worth being precise here: scrambled disulfides have the same mass as correctly formed ones, so mass spectrometry alone cannot detect a scrambling failure.

A mass shift of minus eighteen usually means dehydration or a succinimide intermediate, which is pH-dependent and can be reversible.

More usefully, high-resolution mass spectrometry can distinguish a Lys-containing peptide from an Arg-containing peptide of similar mass because of the isotope difference.

The caveat is that a correct mass does not mean the peak is correct — isomers and co-eluting species can have the same m/z.

Always run a blank between samples and check for carry-over.

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answeredines_delacruz16k1723 Mar 2026
7

Stated carefully, a D-amino-acid substitution has the same molecular weight as the L-form, so mass spectrometry cannot distinguish them without fragmenting the peptide.

A mass shift of minus one hundred and twenty-eight usually means a missing Gln or Lys residue from a synthesis deletion sequence.

Mechanically, the baseline noise on a mass spectrum sets the limit of detection, and a weak signal close to the noise is not reliable evidence for the presence of a species.

Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.

The practical summary: use mass spectrometry for identity, not for purity.

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KL
answeredkelvin_lam11k173 Apr 2026
7Confirming from the other direction: I did the wrong thing and got exactly the predicted outcome. – nkem_obiora 7 months ago
8Is there a reason to prefer the second method over the first, other than cost? – gradient_slope 9 months ago
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