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How do I compute the +2 charge state m/z for a peptide of 3751.0 Da?

Asked 8 May 2026Modified 1 min agoViewed 5.3k times
8

Numbers first: +2 · 3751.0 Da.

This should be a straightforward calculation and I keep getting two different answers.

The numbers are arbitrary; the method is what I am after.

Can someone show the working rather than just the answer?

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TF
askedtwo_point_four14k278 May 2026
3Related: the same reasoning applies to the counter-ion question. – Dr_Colm_Fitzhenry 4 months ago
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4 Answers

Accepted answer first, then by votes
36

Accepted answer

Two ions with the same nominal mass but different molecular formulae have different exact masses, and only high-resolution mass spectrometry can distinguish them.

Electrospray ionisation creates multiple charge states of the same peptide — a 4 kDa peptide might appear at +2, +3 and +4 — and all of them must be accounted for in the spectrum.

Stated carefully, high-resolution mass spectrometry can distinguish a Lys-containing peptide from an Arg-containing peptide of similar mass because of the isotope difference.

False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.

The practical summary: use mass spectrometry for identity, not for purity.

edited 31 Jul 2026 by vialroom — clarified the distinction between purity and content

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answered · acceptedvialroom87k14826 Jul 2026
Is there a reason to prefer the second method over the first, other than cost? – birk_nordahl 4 months ago
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14

On the detail: identity confirmation from mass spectrometry means matching the observed m/z to the calculated m/z for your peptide at its known charge states.

A monoisotopic mass includes only the lightest isotope of each element, while the average mass weights by natural isotope abundance, and small peptides use monoisotopic mass.

The m/z accuracy achievable depends on the mass analyser type — quadrupole gives low accuracy, time-of-flight gives moderate accuracy, and Orbitrap gives high accuracy.

The caveat is that a correct mass does not mean the peak is correct — isomers and co-eluting species can have the same m/z.

Always run a blank between samples and check for carry-over.

edited 11 Jul 2026 by tabular_nums — added the citation requested in comments

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answeredtabular_nums47k3825 Jun 2026
I would add a sentence about sterility here, since it is the thing people skip. – lyoph_cake 2 months ago
8The placebo-arm figure is the part everyone omits. – w_okoye 26 days ago
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11

Concretely, mass spectrometry is an identity technique, not a purity technique, and conflating the two is a common source of false confidence.

The baseline noise on a mass spectrum sets the limit of detection, and a weak signal close to the noise is not reliable evidence for the presence of a species.

More usefully, the charge state distribution depends on the solution pH, the structure of the peptide and the source conditions, so the same peptide can look different under different conditions.

Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

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answeredtare_and_weigh18k286 Jul 2026
9

More usefully, coupling HPLC to a mass spectrometer adds identity information to the chromatographic separation, but the mass spectrometer's ionisation conditions can distort the HPLC peak shape.

For a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.

The practical summary: use mass spectrometry for identity, not for purity.

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DS
answeredDr_Hanne_Solberg40k385 Jun 2026
This matches what I was told by a laboratory, for whatever that is worth. – marta_okonkwo 5 months ago
Minor: the trial name is hyphenated in the original publication. – kirsi_lahtinen 4 months ago
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