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Does racemisation dominate for orforglipron held at 2–8 °C?

Asked 10 Feb 2025Modified 14 months agoViewed 22k times
29

What I have: racemisation · orforglipron · 2–8 °C.

I suspect the usual explanation for this is wrong, or at least incomplete.

I am aware this may have a boring answer. I would still like the boring answer stated clearly.

So what is the mechanism, and how well established is it?

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DH
askedDr_Jonas_Halvorsen41k3810 Feb 2025

5 Answers

Accepted answer first, then by votes
72

Accepted answer

Specifically, degradation is not one process, and which one dominates depends on the condition you are asking about. In solution at refrigerated temperature the rate-limiting pathway is usually deamidation and hydrolysis; at room temperature aggregation overtakes them; frozen, the damage happens during the transitions rather than during the hold.

Light matters for specific residues rather than in general. Tryptophan and to a lesser extent tyrosine and methionine are photo-labile; a sequence without them is largely indifferent to ambient light over the timescales in question. Amber glass is cheap insurance rather than a requirement.

For the solid state, residual moisture is the dominant variable. A cake at two per cent water is considerably more stable than the same cake at six per cent, because water is both a reactant in hydrolysis and a plasticiser that lowers the glass transition temperature. This is why a desiccant in the outer packaging is not theatre, and why opening a cold vial in a humid room is a genuine error — you condense water onto the cake.

Where community-submitted samples with known thermal excursions have been tested at Janoshik or Medutest, the recurring finding is that lyophilised material tolerates warm transit far better than intuition suggests, while reconstituted material shipped warm does not. The asymmetry is consistent enough to plan around.

The limitation is that you cannot detect slow aggregation by eye until it is well advanced, so a clear vial is weak evidence of an intact one.

Store solid, store cold, store dry, and reconstitute what you will use rather than what fits in the vial.

edited 5 May 2025 by sasha_ferreira — tightened the wording; no substantive change

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SF
answered · acceptedsasha_ferreira15k1613 Apr 2025
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29

Start by separating chemical degradation from physical degradation, because they fail differently and they are detected differently. Chemical degradation changes the molecule and shows up as new peaks on a chromatogram. Physical degradation aggregates the molecule and often shows up as nothing at all on reverse-phase HPLC, because the aggregate never makes it onto the column.

Aggregation is the failure mode that reverse-phase HPLC is worst at detecting, because a large soluble aggregate may not elute at all and an insoluble one is filtered out during sample preparation. If your purity result comes back normal but the vial looks hazy, believe the vial. Size-exclusion chromatography is the method that sees this.

Adsorption to the container is a real loss at low concentration. For a peptide at 0.1 mg/mL in an untreated glass vial, single-digit percentage losses to the wall are plausible; at 5 mg/mL it is negligible. This is one of several reasons not to reconstitute to a very dilute working solution and store it.

I would be careful about generalising across sequences. Stability is sequence-specific, and a rule derived from semaglutide will not transfer cleanly to a tri-agonist with different residues in different local environments.

The single highest-value change most people can make is buying a cheap logging thermometer, because it converts an assumption about their storage into a record.

edited 5 Apr 2025 by tobias_maartens — updated for the 2026 guidance change

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TM
answeredtobias_maartens94k2582 Apr 2025
I have seen exactly this failure mode twice and both times it was the diluent. – ines_delacruz 6 months ago
The distinction between purity and content cannot be repeated often enough here. – plate_count_9k 4 months ago
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23

Concretely, a warm arrival is a reason to test, not automatically a reason to discard. Peptide degradation is kinetic — rate multiplied by time — and a few days at thirty degrees in the solid state is a small integral compared to weeks in solution.

The temperature dependence is roughly Arrhenius over the range that matters, which in practice means every ten degrees of increase roughly doubles to triples the rate. Ten days at thirty degrees is therefore comparable to something on the order of a month or two at four degrees — bad, but not the catastrophe it feels like when you open a warm parcel.

The 28-day figure for a reconstituted preserved vial is microbiological, not chemical. Chemically, a well-behaved peptide at 5 mg/mL at 4 °C will typically lose well under a per cent of content per month. The reason to respect the date is bioburden, and bioburden is a function of how many times you have opened it, not of the calendar.

Worth stating: research-use-only material has no stability programme behind it at all, so any beyond-use date you apply is your own construct.

If the material arrived warm and it was lyophilised, test it and proceed on the result. If it arrived warm and it was in solution, the result is more likely to be interesting than reassuring.

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AB
answeredassay_blank39k385 May 2025
19

The honest answer is that published stability data for these specific molecules in a research-grade presentation essentially does not exist, so what you get is extrapolation from the licensed formulations and from general peptide chemistry. That extrapolation is reasonable. It is still extrapolation.

Practical thermal arithmetic for a shipment: a single 250 g phase-change pack in a thin-walled polystyrene box holds sub-ten-degrees for roughly 24 to 48 hours in a 25 °C ambient, and considerably less at 35 °C. Any lane taking eight to fourteen days is therefore not temperature-controlled for most of its duration regardless of what was in the box, which is the argument for shipping the material lyophilised.

Minimise transitions rather than minimising temperature. One freeze and one thaw is fine; five is a different question.

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AZ
answeredahmed_zerouali19k2824 Apr 2025
12

Freeze-thaw damage happens at the moving ice front, not at the storage temperature. Once the sample is frozen solid and cold, very little is happening. The damage is done during freezing and thawing, which is why the number of cycles matters and the duration of the hold mostly does not.

Freeze-concentration is the mechanism people miss. As ice forms, everything that is not water is excluded into a shrinking unfrozen fraction, so the local concentration of peptide, buffer salts and preservative rises sharply. If the buffer components crystallise at different rates, local pH can shift by more than a unit. That is why a phosphate-buffered solution can behave badly on freezing while an unbuffered one is fine.

General guidance on lyophilised peptide storage from the major synthesis houses converges on minus twenty degrees for long-term storage of solids and refrigerated storage for solutions in use, with the explicit note that repeated freeze-thaw of solutions should be avoided. It is consistent advice precisely because it follows from the chemistry rather than from a study.

The practical rule is that time and temperature multiply, so shorten whichever one you control.

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SB
answereds_bhattacharya42k3828 May 2025
7The timing signature is the useful part. Everything else is confounded. – bea_castellanos 3 months ago
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