Accepted answer
Three days at minus 80 °C. minus 80 °C is 85 kelvin below a refrigerator, and below the glass transition of a lyophilised cake the ten-degree rule of thumb stops applying at all — solid-state chemistry is not slow liquid chemistry, it is a different regime, and the failure modes that survive it are mechanical rather than chemical. The thing to establish is how many times it froze and thawed, not how long it sat: three days at one stable temperature is gentler than a single uncontrolled transition. Either way, record the three days and the temperature now, while you still know them; an excursion you did not write down is an excursion you cannot interpret later.
The short version: a spent cold pack on arrival is expected, the solid does not mind, and the pack was never going to last twelve days.
A single phase-change pack in a thin-walled box holds below ten degrees for roughly one to two days at twenty-five degrees ambient, and under a day at thirty-five. On a nine-to-fourteen-day lane the material is at ambient for most of the journey whatever was packed with it.
To be exact about it, arrhenius behaviour means the degradation rate roughly doubles per ten degrees. A week at thirty degrees is therefore a meaningful exposure for a solution and an immaterial one for a dry solid.
Phase-change pack hold time is a function of mass, latent heat and insulation, and published figures for small parcels are on the order of one to two days.
The caveat is that a warm transit is survivable for a solid and materially different for a solution.
Lyophilised tolerates the lane. That is the answer for almost every order.