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How do I compute the +2 charge state m/z for a peptide of 4207.2 Da?

Asked 23 Sept 2024Modified 18 months agoViewed 31k times
35

What I have: +2 · 4207.2 Da.

This should be a straightforward calculation and I keep getting two different answers.

The numbers are arbitrary; the method is what I am after.

Can someone show the working rather than just the answer?

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LB
askedliam_bracken6.9k1423 Sept 2024

5 Answers

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19

m/z = 2104.61 at 2+. Electrospray charges a peptide by adding protons, so the observed ion is the neutral mass plus 2 protons, all divided by the charge: (4207.2 + 2 × 1.00728) ÷ 2 = 4209.215 ÷ 2 = 2104.61. The proton term is the one people drop, and because it is z protons over z charges it shifts m/z by 1.007 at every charge state — small, and far larger than the mass accuracy of the instrument. The neighbouring charge state sits at 1403.41, and seeing the two of them where they belong is better identity evidence than either one alone. Use the average mass against an average-mass calculation and the monoisotopic mass against a monoisotopic one; mixing them costs you a couple of daltons on a peptide this size.

Put another way, a mass shift of exactly zero with a shifted retention time points to an isomer — a scrambled disulfide or a racemised residue — which mass spectrometry alone cannot identify.

A mass shift of minus one hundred and twenty-eight usually means a missing Gln or Lys residue from a synthesis deletion sequence.

Mass shifts and what they usually mean

Δ mass (Da)Most likely causeDistinguishing feature
+1Deamidation (Asn or Gln)New peak, slightly earlier retention
−17Loss of ammoniaOften with deamidation
−18Dehydration / succinimidepH-dependent, reversible
+16Oxidation (Met, Trp)Earlier retention, light-related
−128Missing Gln or LysDeletion sequence from synthesis
0Isomer: racemisation or scramblingSame mass, shifted retention

To be exact about it, the baseline noise on a mass spectrum sets the limit of detection, and a weak signal close to the noise is not reliable evidence for the presence of a species.

False positives from contamination are common in mass spectrometry work, and running a blank between every sample and a solvent background are standard practice.

The caveat is that a correct mass does not mean the peak is correct — isomers and co-eluting species can have the same m/z.

The practical summary: use mass spectrometry for identity, not for purity.

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TG
answeredtandem_gradient61k24818 Jan 2025
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15

On the detail: the single most important fact about mass spectrometry for peptides is that it measures only the molecular weight and tells you almost nothing about whether the peak is actually your target.

Deconvolution of a mass spectrum with multiple charge states produces a reconstructed neutral mass, and errors in the deconvolution produce errors in the inferred mass.

The m/z accuracy achievable depends on the mass analyser type — quadrupole gives low accuracy, time-of-flight gives moderate accuracy, and Orbitrap gives high accuracy.

Always run a blank between samples and check for carry-over.

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OF
answeredorla_ferriter89k14823 Oct 2024
8The system-suitability data is the part that tells you whether to believe the rest. – e_dziedzic 8 months ago
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13

Scrambled disulfides have the same mass as correctly formed ones, so mass spectrometry alone cannot detect a scrambling failure.

The charge state distribution depends on the solution pH, the structure of the peptide and the source conditions, so the same peptide can look different under different conditions.

More usefully, for a large peptide with multiple peaks in the mass spectrum, comparing the observed isotope pattern to the calculated pattern is a quick check that the formula matches.

Worth noting that source contamination is common and silent, so a result that looks too good to be true often is.

A correct mass is necessary for identity but not sufficient — you also need the chromatography to confirm it.

edited 20 Oct 2024 by mz_4113 — added the method parameters

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M4
answeredmz_4113101k35812 Oct 2024
8The distinction between purity and content cannot be repeated often enough here. – orla_ferriter 13 days ago
7The impurity table is the part I now read first, and this explains why. – ines_brandt 9 months ago
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12

Identity confirmation from mass spectrometry means matching the observed m/z to the calculated m/z for your peptide at its known charge states.

High-resolution mass spectrometry can distinguish a Lys-containing peptide from an Arg-containing peptide of similar mass because of the isotope difference.

Peptide mapping — enzymatic digestion followed by tandem mass spectrometry — can confirm the primary sequence and is the method of choice when identity is ambiguous.

If you only pay for one test, pay for quantified content. Purity is the number everyone quotes and content is the number that changes what you do.

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DV
answeredDr_Bram_Verhoeven84k24816 Dec 2024
3Which wavelength was the purity integrated at? It changes the number more than people think. – petra_hovland 6 months ago
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-3

Tandem mass spectrometry fragments the ions and measures the fragment masses, which provides sequence information and is the best tool for confirming identity.

A mass shift of plus sixteen usually means oxidation at methionine or tryptophan, which is common in peptides and often comes from sample handling rather than synthesis failure.

In practice: ask for the chromatogram, check the method section, check the lot number against the vial, and set your accept threshold before you see the result rather than after.

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BD
answeredb_delacroix43k381 Oct 2024

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