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What happens to liraglutide after three weeks at minus 80 °C in solution?

Asked 2 Jan 2026Modified 6 months agoViewed 9.7k times
10

For reference: liraglutide · three weeks · minus 80 °C.

I understand the observation; what I do not understand is the mechanism behind it.

I have read the two review articles that come up first and both assert this without a citation to a primary source.

So what is the mechanism, and how well established is it?

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DW
askedDr_Elias_Weiss25k272 Jan 2026

3 Answers

Accepted answer first, then by votes
94

Accepted answer

three weeks is 21 days at a temperature where the chemistry all but stops and the physics does not. minus 80 °C is 85 kelvin below a refrigerator, and below the glass transition of a lyophilised cake the ten-degree rule of thumb stops applying at all — solid-state chemistry is not slow liquid chemistry, it is a different regime, and the failure modes that survive it are mechanical rather than chemical. In a frozen solution the solute is excluded from the growing ice, so the unfrozen fraction concentrates and the buffer's pH moves as one salt crystallises before the other. The damage is done at the transitions, and 21 days of stable hold between them contributes very little. Reconstituted material has no certificate; the one in the box describes the powder.

Answer first: the degradation pathways worth knowing are hydrolysis, deamidation, oxidation, aggregation and adsorption, and each has a different trigger and a different mitigation.

Adsorption onto glass and plastic is significant at low concentrations — micrograms per millilitre — and negligible at milligrams per millilitre. It is the usual explanation for an apparent loss in a dilute preparation.

Hydrolysis cleaves the backbone, most readily at aspartate-proline and aspartate-glycine sequences, and is acid-catalysed. In a dry solid it barely proceeds at all.

Deamidation via the succinimide intermediate is well characterised, with sequence-dependent rates highest for asparagine-glycine motifs.

At dilute concentrations, suspect adsorption before you suspect chemistry.

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EV
answered · acceptedekaterina_volk21k287 Feb 2026
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37

The honest answer is that most reported "degradation" is adsorption and dilution error rather than chemistry.

Oxidation targets methionine, cysteine and tryptophan, adding sixteen daltons per oxygen. It is catalysed by trace metals and promoted by dissolved oxygen and by light.

A mass spectrum resolves most of this: minus eighteen is dehydration or succinimide, plus one is deamidation, plus sixteen is oxidation, and an unchanged mass with a shifted retention time is an isomer.

Sequence decides which pathways are even available. Check the residues.

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TU
answeredtenth_of_a_unit57k3727 Jan 2026
5Adding a vote because this deserves more of them. – plate_count_9k 44 days ago
4Does the same reasoning apply to material already in solution, or is that a different curve? – p_mkhize 10 months ago
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27

Answering this needs the physical state, since a dry powder is protected from most of these and a solution is protected from none.

Deamidation converts asparagine or glutamine to the corresponding acid via a succinimide intermediate, adding one dalton. It is base-catalysed, accelerates above neutral pH and is the dominant aqueous pathway for many peptides.

Freeze-thaw cycling drives aggregation through concentration at the ice interface and pH shifts as buffer components crystallise out at different rates. Each cycle costs something.

Adsorption losses at low concentrations are quantified in formulation studies and are the reason carrier proteins are used in dilute preparations.

Cold, dry, dark, still. Those four words cover most of the mitigation.

edited 6 Feb 2026 by h_pergande — clarified the distinction between purity and content

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HP
answeredh_pergande71k15816 Jan 2026
4Is there a reason to prefer minus eighty here, or is minus twenty genuinely enough? – two_two_micron 4 months ago
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